5x^2-7x+39=0

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Solution for 5x^2-7x+39=0 equation:


Simplifying
5x2 + -7x + 39 = 0

Reorder the terms:
39 + -7x + 5x2 = 0

Solving
39 + -7x + 5x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
7.8 + -1.4x + x2 = 0

Move the constant term to the right:

Add '-7.8' to each side of the equation.
7.8 + -1.4x + -7.8 + x2 = 0 + -7.8

Reorder the terms:
7.8 + -7.8 + -1.4x + x2 = 0 + -7.8

Combine like terms: 7.8 + -7.8 = 0.0
0.0 + -1.4x + x2 = 0 + -7.8
-1.4x + x2 = 0 + -7.8

Combine like terms: 0 + -7.8 = -7.8
-1.4x + x2 = -7.8

The x term is -1.4x.  Take half its coefficient (-0.7).
Square it (0.49) and add it to both sides.

Add '0.49' to each side of the equation.
-1.4x + 0.49 + x2 = -7.8 + 0.49

Reorder the terms:
0.49 + -1.4x + x2 = -7.8 + 0.49

Combine like terms: -7.8 + 0.49 = -7.31
0.49 + -1.4x + x2 = -7.31

Factor a perfect square on the left side:
(x + -0.7)(x + -0.7) = -7.31

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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